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 Wysłany: Pon 22:25, 17 Sty 2011 Temat postu: Inverse trigonometric functions and simple trigono |
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Inverse trigonometric functions and simple trigonometric
arctgb ∈ [0,[link widoczny dla zalogowanych],5 A -). _. arctga + arctgb = curse, was chosen (B) examine how the commentary arctangent trigonometric computing demand angle. Identified in the corners and take the function of a monotone interval is the key to solving problems. 5. Solution. . sinl0 = sin (3 ~ a 10),[link widoczny dla zalogowanych], and 3 to 10E [14,[link widoczny dla zalogowanych],16 a 2001 Communication of Mathematics 37, No. arcsin (sin10) arcsin [sin (3 a 10)] = 3 to 10. Was chosen (C). Note the commentary formula arcsin (sitar) = X set up conditions. For non-corner of the main value of the interval is usually induced by the formula used by the main value of the interval into a corner on that. 6. Solutions were made Y1 = sin2x, y2 = arcsinx function image shows three intersections, the number of solutions to 3,[link widoczny dla zalogowanych], was chosen (C). The Combination of timely commentary by way of thinking, problem solving help. 7. Solution is clearly n, b,[link widoczny dla zalogowanych], cE (0, number), and sin (arcsin Temple) = {'Sin (arco0s3) = n (arctg) = Pi, and 1 0,. '. arccos (3 a n) a ≤ 1,. *. the domain of [2,3-a). Also arcms (3 a x) E [0, · curse a arcms (3 a) E (0,6], can be obtained by the words of the range of (a oo, curse]. The commentary of the form Y = arcsin [ ,],[the domain of .10. canthal = No solution is given by si, if ∈ (0, number], the arcsin 1; if ∈ (number), then =- arin _ No. 13 by the si canthus = a, there sin (a ) = 1, another E (0, No. ),.·.=+ arcsin number. Analysis of trigonometric solutions, the use of inverse trigonometric functions that specify the interval formula angle commonly induced transformation, or directly derived equations all the solutions together and then find the solution of questions asked .11. Solutions Let a = i \, and a one Lu E (0,), and sin (a a) = 1,. ·. arin number one by one In (a 4) = number. Note the commentary and analysis of the deformation angle of the scope of skills .12. Solutions . 'E [0,] and oos (∞) = 0,. ·. ∞ Chi on the 10th, Chi = 0 or a 1, that was o06 ± Kyrgyzstan. and E [0, so ],.·. solution set is {number, police, police}. commentary examines the main issues trigonometric Solution .13. solution is given by sin (2x One) = 0 and cos (2x One) ≠ 1, to know cos (2x One) = a '* Chi + Police (Chi ∈ z). commentary examines the main issues the ability to analyze problems of reconciliation trigonometric .14. Solutions to set port = arcsinx. Pui 0Y = 1-2x +2 x +1 = A 2 (x-1) on the 10th, Another 1 ≤ ≤ 1 and a 1 ≤ 2 +1 ≤ 1,. '. a 1 ≤ ≤ 0,.'. When X = a 1, = a 2, when X = 0 when ~ = 2. Commentary examine the domain of the inverse trigonometric functions of the basic formula of computing the value of a function control method and the palm Osmanthus fragrans.
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